Suppose I have a protocol that contains a method with a default implementation:
public protocol A {
func foo()
}
public extension A {
func foo() {
print("A.foo()")
}
}
Now in a class that conforms to this protocol, I know I can call the method (and get the default implementation) or override the method (and get my own implementation).
QUESTION: Is it possible to EXTEND the default implementation. What I'd like to do is write something like:
class X : A {
func foo() {
A.foo()
print("X.foo()")
}
}
X.foo() // prints
// "A.foo()"
// "X.foo()"
This does not, of course, compile. But you can see what I want to do.
Is this possible? If so, how? (The alternative seems to be to repeat the default implementation everywhere we customize the method, which is a real mess if we ever change the content of the default implementation.)
